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Re: [TowerTalk] Metal Thermal Rate of Expansion

To: "'towertalk@contesting.com'" <towertalk@contesting.com>
Subject: Re: [TowerTalk] Metal Thermal Rate of Expansion
From: Grant Saviers <grants2@pacbell.net>
Date: Mon, 4 Oct 2021 12:58:26 -0700
List-post: <mailto:towertalk@contesting.com>
Expansion in an isotropic media such as most metals is the same in all directions. Think of enlarging something for printing by a fraction of a percent.

Everything gets larger by the coefficient of expansion/deg C. Thus, holes get larger, OD's get larger, and circumference the same as Diameter * pi. A shrink fit only needs to consider the radial interference that is desired.

The 0.00034" change in the radial gap I calculated for 100 deg C temperature change is meaningless if the two parts were slipped together by hand. It doesn't matter in this case whether the inside part has a higher coefficient of expansion or not, since the gap machined as was described was certainly several thousandth of an inch.

Extruded tubing is not round and welded pipe/tubing is even more out of round, which is probably why the machining was needed.

Grant KZ1W

On 10/4/2021 11:21, David Gilbert wrote:

I'm not sure that percentage of expansion is the relevant consideration here.  I would think that the gap between the cylinders (i.e., portion of the diameter) is the important part, and since the expansion occurs in the circumference the gap changes by a factor of pi less.

Even less reason to be concerned, I think.

73,
Dave   AB7E



On 10/4/2021 8:00 AM, Lux, Jim wrote:

Circumference and diameter grow by the same percentage (since C = d * pi), so CTE wise, it's the same whether you use diameter or circumference.


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